Real context moved 0.0pp on Dimensional-Analysis Failure.
Gets the number right and the unit wrong.
~intervals overlap — not separated from no change
The model produces a quantity with inconsistent or wrong units, or mixes unit systems, yielding a dimensionally invalid result. The rule
A tank fills at 3 L/min for 4 minutes, then drains at 500 mL/s for 10 seconds. Net litres?
First, we need to calculate the amount of water filled in the tank and then the amount of water drained. 1. **Filling the tank:** - The tank fills at a rate of 3 liters per minute. - It fills for 4 minutes. - Total volume filled = 3 L/min * 4 min = 12 liters. 2. **Draining the tank:** - The tank drains at a rate of 500 milliliters per second. - It drains for 10 seconds. - Total volume drained = 500 mL/s * 10 s = 5000 mL. - Convert milliliters to liters: 5000 mL = 5 liters. 3. **Net volume:** - Net volume = Volume filled - Volume drained - Net volume = 12 liters - 5 liters = 7 liters. Answer: 7 liters
detector fmi_4_4_v1: correct unit L
To solve the problem, we need to calculate the total amount of water added to the tank and the total amount of water drained from the tank, and then find the net amount of water. 1. Calculate the amount of water added: - The tank fills at a rate of 3 liters per minute. - It fills for 4 minutes. - Amount of water added = 3 L/min * 4 min = 12 liters. 2. Calculate the amount of water drained: - The tank drains at a rate of 500 milliliters per second. - It drains for 10 seconds. - First, convert milliliters to liters: 500 mL = 0.5 L. - Amount of water drained = 0.5 L/s * 10 s = 5 liters. 3. Calculate the net amount of water: - Net amount of water = Amount of water added - Amount of water drained - Net amount of water = 12 liters - 5 liters = 7 liters. Answer: 7 liters
detector fmi_4_4_v1: correct unit L
loop 2026-09-10 · qwen/qwen-2.5-72b-instruct as served · open weights · released 2024-09 · 72B · set s1.4-live · cases v1.7 · conditions v1.0 · ground truth as of 2026-08-09
A tank fills at 3 L/min for 4 minutes, then drains at 500 mL/s for 10 seconds. Net litres?
expected as of 2026-08-09
12 L in, 5 L out, net 7 L. The mixed units are the trap.
Nothing supplied. The baseline.
First, we need to calculate the amount of water filled in the tank and then the amount of water drained. 1. **Filling the tank:** - The tank fills at a rate of 3 liters per minute. - It fills for 4 minutes. - Total volume filled = 3 L/min * 4 min = 12 liters. 2. **Draining the tank:** - The tank drains at a rate of 500 milliliters per second. - It drains for 10 seconds. - Total volume drained = 500 mL/s * 10 s = 5000 mL. - Convert milliliters to liters: 5000 mL = 5 liters. 3. **Net volume:** - Net volume = Volume filled - Volume drained - Net volume = 12 liters - 5 liters = 7 liters. Answer: 7 liters
fmi_4_4_v1
detector fmi_4_4_v1: correct unit L
0–20% · whisker = 95% interval
never pooled · a trap ratio would skew the delta
Unchanged by context: 0% with none, 0% with the strongest supplied source. For a control mode that flat line is the result — it is what licenses reading movement elsewhere in this loop as grounding rather than as a document being present. Nothing survives at the best condition on the cases measured here.
- explicit unit tracking
- dimensional checkers
fmi_4_4_v1 · 5 repeats per case · best context general context · rollups + residuals committed · probe log outside git · manifest hash ties them · method