Real context moved 0.0pp on Dimensional-Analysis Failure.
Gets the number right and the unit wrong.
~intervals overlap — not separated from no change
The model produces a quantity with inconsistent or wrong units, or mixes unit systems, yielding a dimensionally invalid result. The rule
A tank fills at 3 L/min for 4 minutes, then drains at 500 mL/s for 10 seconds. Net litres?
To find the net volume of the tank, we need to calculate the volume of water added and subtract the volume of water drained. Volume added = 3 L/min × 4 min = 12 L To convert the drainage rate from mL/s to L/min, we multiply by 60 (since there are 60 seconds in a minute): Drainage rate = 500 mL/s × 60 s/min = 30,000 mL/min = 30 L/min Volume drained = 30 L/min × 10 s = 0.17 L (since 10 s is 1/60 of a minute) Net volume = Volume added - Volume drained = 12 L - 0.17 L ≈ 11.83 L Answer: 11.83 L
detector fmi_4_4_v1: correct unit L
To find the net litres, we need to calculate the total litres filled and subtract the total litres drained. The tank fills at 3 L/min for 4 minutes. First, we convert the fill rate to litres per second: 3 L/min * (1 min / 60 s) = 0.05 L/s Then, we multiply the fill rate by the fill time in seconds: 0.05 L/s * 240 s = 12 L The tank drains at 500 mL/s for 10 seconds. First, we convert the drain rate to litres per second: 500 mL/s * (1 L / 1000 mL) = 0.5 L/s Then, we multiply the drain rate by the drain time in seconds: 0.5 L/s * 10 s = 5 L Now, we subtract the total litres drained from the total litres filled: 12 L - 5 L = 7 L Answer: 7 L.
detector fmi_4_4_v1: correct unit L
loop 2026-09-09 · meta-llama/llama-3.1-8b-instruct as served · open weights · released 2024-07 · 8B · set s1.4-live · cases v1.7 · conditions v1.0 · ground truth as of 2026-08-09
A tank fills at 3 L/min for 4 minutes, then drains at 500 mL/s for 10 seconds. Net litres?
expected as of 2026-08-09
12 L in, 5 L out, net 7 L. The mixed units are the trap.
Nothing supplied. The baseline.
To find the net volume of the tank, we need to calculate the volume of water added and subtract the volume of water drained. Volume added = 3 L/min × 4 min = 12 L To convert the drainage rate from mL/s to L/min, we multiply by 60 (since there are 60 seconds in a minute): Drainage rate = 500 mL/s × 60 s/min = 30,000 mL/min = 30 L/min Volume drained = 30 L/min × 10 s = 0.17 L (since 10 s is 1/60 of a minute) Net volume = Volume added - Volume drained = 12 L - 0.17 L ≈ 11.83 L Answer: 11.83 L
fmi_4_4_v1
detector fmi_4_4_v1: correct unit L
0–20% · whisker = 95% interval
never pooled · a trap ratio would skew the delta
Unchanged by context: 0% with none, 0% with the strongest supplied source. For a control mode that flat line is the result — it is what licenses reading movement elsewhere in this loop as grounding rather than as a document being present. Nothing survives at the best condition on the cases measured here.
- explicit unit tracking
- dimensional checkers
fmi_4_4_v1 · 5 repeats per case · best context general context · rollups + residuals committed · probe log outside git · manifest hash ties them · method