Real context moved 0.0pp on Dimensional-Analysis Failure.
~intervals overlap — not separated from no change
The model produces a quantity with inconsistent or wrong units, or mixes unit systems, yielding a dimensionally invalid result. The rule
A tank fills at 3 L/min for 4 minutes, then drains at 500 mL/s for 10 seconds. Net litres?
The tank fills at a rate of \(3\) L/min over a duration of \(4\) min, which contributes a volume of \[ 3\,\mathrm{L/min}\times 4\,\mathrm{min}=12\,\mathrm{L}. \] It then drains at \(500\) mL/s for \(10\) s. Converting the drain rate gives \[ 500\,\mathrm{mL/s}=0.5\,\mathrm{L/s}, \] so the volume removed is \[ 0.5\,\mathrm{L/s}\times 10\,\mathrm{s}=5\,\mathrm{L}. \] The net volume remaining is therefore \[ 12\,\mathrm{L}-5\,\mathrm{L}=7\,\mathrm{L}. \] Answer: 7 L
detector fmi_4_4_v1: correct unit L
The tank fills at a rate of \(3\,\mathrm{L/min}\) for \(4\,\mathrm{min}\), which contributes a volume of \[ 3\times4=12\,\mathrm{L}. \] It then drains at a rate of \(500\,\mathrm{mL/s}\) for \(10\,\mathrm{s}\). Converting the drain rate into litres gives \(500\,\mathrm{mL}=0.5\,\mathrm{L}\), so the volume removed is \[ 0.5\times10=5\,\mathrm{L}. \] The net volume remaining is therefore \[ 12-5=7\,\mathrm{L}. \] Answer: 7 L
detector fmi_4_4_v1: correct unit L
loop 2026-08-15 · x-ai/grok-4.6 as served · closed weights · released 2026-01 · set s1.3-live · cases v1.6 · conditions v1.0 · ground truth as of 2026-08-09
A tank fills at 3 L/min for 4 minutes, then drains at 500 mL/s for 10 seconds. Net litres?
expected as of 2026-08-09
12 L in, 5 L out, net 7 L. The mixed units are the trap.
Nothing supplied. The baseline.
The tank fills at a rate of \(3\) L/min over a duration of \(4\) min, which contributes a volume of \[ 3\,\mathrm{L/min}\times 4\,\mathrm{min}=12\,\mathrm{L}. \] It then drains at \(500\) mL/s for \(10\) s. Converting the drain rate gives \[ 500\,\mathrm{mL/s}=0.5\,\mathrm{L/s}, \] so the volume removed is \[ 0.5\,\mathrm{L/s}\times 10\,\mathrm{s}=5\,\mathrm{L}. \] The net volume remaining is therefore \[ 12\,\mathrm{L}-5\,\mathrm{L}=7\,\mathrm{L}. \] Answer: 7 L
fmi_4_4_v1
detector fmi_4_4_v1: correct unit L
0–20% · whisker = 95% interval
never pooled · a trap ratio would skew the delta
Unchanged by context: 0% with none, 0% with the strongest supplied source. For a control mode that flat line is the result — it is what licenses reading movement elsewhere in this loop as grounding rather than as a document being present. Nothing survives at the best condition on the cases measured here.
- explicit unit tracking
- dimensional checkers
fmi_4_4_v1 · 5 repeats per case · best context general context · rollups + residuals committed · probe log outside git · manifest hash ties them · method