Real context moved 0.0pp on Dimensional-Analysis Failure.
~intervals overlap — not separated from no change
The model produces a quantity with inconsistent or wrong units, or mixes unit systems, yielding a dimensionally invalid result. The rule
A tank fills at 3 L/min for 4 minutes, then drains at 500 mL/s for 10 seconds. Net litres?
First, calculate the amount of water added to the tank during the filling process: The tank fills at a rate of 3 liters per minute for 4 minutes. Amount filled = 3 L/min × 4 min = 12 liters Next, calculate the amount of water drained from the tank: The tank drains at a rate of 500 mL/s for 10 seconds. First, convert the drainage rate from milliliters to liters: 500 mL = 0.5 L Amount drained = 0.5 L/s × 10 s = 5 liters Now, calculate the net amount of water in the tank: Net amount = Amount filled - Amount drained Net amount = 12 liters - 5 liters = 7 liters Answer: 7 liters
detector fmi_4_4_v1: correct unit L
To solve this problem, we need to calculate the total amount of water added to the tank and then subtract the amount of water drained from the tank. First, calculate the amount of water added to the tank: - The tank fills at a rate of 3 liters per minute for 4 minutes. - Total water added = 3 L/min × 4 min = 12 liters. Next, calculate the amount of water drained from the tank: - The tank drains at a rate of 500 milliliters per second for 10 seconds. - Since 1 liter = 1000 milliliters, 500 milliliters = 0.5 liters. - Total water drained = 0.5 L/s × 10 s = 5 liters. Finally, calculate the net amount of water in the tank: - Net water = Total water added - Total water drained = 12 liters - 5 liters = 7 liters. Answer: 7 liters
detector fmi_4_4_v1: correct unit L
loop 2026-08-15 · openai/gpt-4o as served · closed weights · released 2024-05 · set s1.3-live · cases v1.6 · conditions v1.0 · ground truth as of 2026-08-09
A tank fills at 3 L/min for 4 minutes, then drains at 500 mL/s for 10 seconds. Net litres?
expected as of 2026-08-09
12 L in, 5 L out, net 7 L. The mixed units are the trap.
Nothing supplied. The baseline.
First, calculate the amount of water added to the tank during the filling process: The tank fills at a rate of 3 liters per minute for 4 minutes. Amount filled = 3 L/min × 4 min = 12 liters Next, calculate the amount of water drained from the tank: The tank drains at a rate of 500 mL/s for 10 seconds. First, convert the drainage rate from milliliters to liters: 500 mL = 0.5 L Amount drained = 0.5 L/s × 10 s = 5 liters Now, calculate the net amount of water in the tank: Net amount = Amount filled - Amount drained Net amount = 12 liters - 5 liters = 7 liters Answer: 7 liters
fmi_4_4_v1
detector fmi_4_4_v1: correct unit L
0–20% · whisker = 95% interval
never pooled · a trap ratio would skew the delta
Unchanged by context: 0% with none, 0% with the strongest supplied source. For a control mode that flat line is the result — it is what licenses reading movement elsewhere in this loop as grounding rather than as a document being present. Nothing survives at the best condition on the cases measured here.
- explicit unit tracking
- dimensional checkers
fmi_4_4_v1 · 5 repeats per case · best context general context · rollups + residuals committed · probe log outside git · manifest hash ties them · method