Real context moved 0.0pp on Dimensional-Analysis Failure.

To find the net litres, we need to calculate the volume of water filled and the volume of water drained. The tank fills at 3 L/min for 4 minutes. To find the volume filled, we multiply the rate of filling (3 L/min) by the time (4 minutes): 3 L/min × 4 min = 12 L The tank then drains at 500 mL/s for 10 seconds. To find the volume drained, we multiply the rate of draining (500 mL/s) by the time (10 seconds). We need to convert the time from seconds to minutes, since the rate of draining is in mL/s: 10 s = 10 s / 60 s/min = 1/6 min Now we multiply the rate of draining (500 mL/s) by the time (1/6 min): 500 mL/s × 1/6 min = 83.33 mL Since we want the answer in litres, we need to convert millilitres to litres: 83.33 mL = 83.33 mL / 1000 mL/L = 0.0833 L Now we subtract the volume drained from the volume filled to find the net litres: 12 L - 0.0833 L = 11.9167 L So the net litres is approximately 11.92 L. Answer: 11.92 L.

detector fmi_4_4_v1: correct unit L