Real context moved 0.0pp on Dimensional-Analysis Failure.
~intervals overlap — not separated from no change
The model produces a quantity with inconsistent or wrong units, or mixes unit systems, yielding a dimensionally invalid result. The rule
A tank fills at 3 L/min for 4 minutes, then drains at 500 mL/s for 10 seconds. Net litres?
To solve this problem, we need to calculate the amount of water filled in the tank and the amount of water drained from the tank, then find the net litres. Given information: - The tank fills at a rate of 3 L/min for 4 minutes. - The tank drains at a rate of 500 mL/s for 10 seconds. Step 1: Calculate the amount of water filled in the tank. Amount of water filled = Filling rate × Time Amount of water filled = 3 L/min × 4 min = 12 L Step 2: Calculate the amount of water drained from the tank. Amount of water drained = Draining rate × Time Amount of water drained = 500 mL/s × 10 s = 5000 mL = 5 L Step 3: Calculate the net litres. Net litres = Amount of water filled - Amount of water drained Net litres = 12 L - 5 L = 7 L Answer: 7 L
detector fmi_4_4_v1: correct unit L
To solve this problem, we need to calculate the total volume of water added to the tank and the total volume of water drained from the tank, and then find the net difference. Given information: - The tank fills at a rate of 3 L/min for 4 minutes. - The tank drains at a rate of 500 mL/s for 10 seconds. Step 1: Calculate the total volume of water added to the tank. Volume added = Filling rate × Time Volume added = 3 L/min × 4 min = 12 L Step 2: Calculate the total volume of water drained from the tank. Volume drained = Draining rate × Time Volume drained = 500 mL/s × 10 s = 5000 mL = 5 L Step 3: Calculate the net volume of water in the tank. Net volume = Volume added - Volume drained Net volume = 12 L - 5 L = 7 L Answer: 7 L
detector fmi_4_4_v1: correct unit L
loop 2026-08-15 · anthropic/claude-3-haiku as served · closed weights · released 2024-03 · set s1.3-live · cases v1.6 · conditions v1.0 · ground truth as of 2026-08-09
A tank fills at 3 L/min for 4 minutes, then drains at 500 mL/s for 10 seconds. Net litres?
expected as of 2026-08-09
12 L in, 5 L out, net 7 L. The mixed units are the trap.
Nothing supplied. The baseline.
To solve this problem, we need to calculate the amount of water filled in the tank and the amount of water drained from the tank, then find the net litres. Given information: - The tank fills at a rate of 3 L/min for 4 minutes. - The tank drains at a rate of 500 mL/s for 10 seconds. Step 1: Calculate the amount of water filled in the tank. Amount of water filled = Filling rate × Time Amount of water filled = 3 L/min × 4 min = 12 L Step 2: Calculate the amount of water drained from the tank. Amount of water drained = Draining rate × Time Amount of water drained = 500 mL/s × 10 s = 5000 mL = 5 L Step 3: Calculate the net litres. Net litres = Amount of water filled - Amount of water drained Net litres = 12 L - 5 L = 7 L Answer: 7 L
fmi_4_4_v1
detector fmi_4_4_v1: correct unit L
0–20% · whisker = 95% interval
never pooled · a trap ratio would skew the delta
Unchanged by context: 0% with none, 0% with the strongest supplied source. For a control mode that flat line is the result — it is what licenses reading movement elsewhere in this loop as grounding rather than as a document being present. Nothing survives at the best condition on the cases measured here.
- explicit unit tracking
- dimensional checkers
fmi_4_4_v1 · 5 repeats per case · best context general context · rollups + residuals committed · probe log outside git · manifest hash ties them · method