Real context moved 0.0pp on Dimensional-Analysis Failure.
~intervals overlap — not separated from no change
The model produces a quantity with inconsistent or wrong units, or mixes unit systems, yielding a dimensionally invalid result. The rule
A tank fills at 3 L/min for 4 minutes, then drains at 500 mL/s for 10 seconds. Net litres?
To find the net litres, we need to calculate the total litres filled and subtract the total litres drained. The tank fills at 3 L/min for 4 minutes, so the total litres filled is: 3 L/min * 4 min = 12 L The tank drains at 500 mL/s for 10 seconds. We need to convert the flow rate to L/s and the time to seconds: 500 mL/s = 0.5 L/s (since 1 L = 1000 mL) 10 seconds (no conversion needed) The total litres drained is: 0.5 L/s * 10 s = 5 L Now, we subtract the total litres drained from the total litres filled: 12 L - 5 L = 7 L Answer: 7 L
detector fmi_4_4_v1: correct unit L
To find the net litres in the tank after the filling and draining process, we need to calculate the total litres filled and subtract the total litres drained. Filling: The tank fills at 3 L/min for 4 minutes. Total litres filled = rate * time = 3 L/min * 4 min = 12 L Draining: The tank drains at 500 mL/s for 10 seconds. First, convert the draining rate to L/s since we are working in litres: 500 mL/s = 0.5 L/s (because 1 L = 1000 mL) Then, calculate the total litres drained: Total litres drained = rate * time = 0.5 L/s * 10 s = 5 L Net litres = Total litres filled - Total litres drained = 12 L - 5 L = 7 L Answer: 7 L
detector fmi_4_4_v1: correct unit L
loop 2026-08-15 · meta-llama/llama-3.3-70b-instruct as served · open weights · released 2024-12 · 70B · set s1.2-live · cases v1.4 · conditions v1.0 · ground truth as of 2026-08-09
A tank fills at 3 L/min for 4 minutes, then drains at 500 mL/s for 10 seconds. Net litres?
expected as of 2026-08-09
12 L in, 5 L out, net 7 L. The mixed units are the trap.
Nothing supplied. The baseline.
To find the net litres, we need to calculate the total litres filled and subtract the total litres drained. The tank fills at 3 L/min for 4 minutes, so the total litres filled is: 3 L/min * 4 min = 12 L The tank drains at 500 mL/s for 10 seconds. We need to convert the flow rate to L/s and the time to seconds: 500 mL/s = 0.5 L/s (since 1 L = 1000 mL) 10 seconds (no conversion needed) The total litres drained is: 0.5 L/s * 10 s = 5 L Now, we subtract the total litres drained from the total litres filled: 12 L - 5 L = 7 L Answer: 7 L
fmi_4_4_v1
detector fmi_4_4_v1: correct unit L
0–20% · whisker = 95% interval
never pooled · a trap ratio would skew the delta
Unchanged by context: 0% with none, 0% with the strongest supplied source. For a control mode that flat line is the result — it is what licenses reading movement elsewhere in this loop as grounding rather than as a document being present. Nothing survives at the best condition on the cases measured here.
- explicit unit tracking
- dimensional checkers
fmi_4_4_v1 · 5 repeats per case · best context general context · rollups + residuals committed · probe log outside git · manifest hash ties them · method