Real context moved 0.0pp on Dimensional-Analysis Failure.
~intervals overlap — not separated from no change
The model produces a quantity with inconsistent or wrong units, or mixes unit systems, yielding a dimensionally invalid result. The rule
A tank fills at 3 L/min for 4 minutes, then drains at 500 mL/s for 10 seconds. Net litres?
To find the net volume, we need to calculate the volume filled and the volume drained. The tank fills at 3 L/min for 4 minutes. First, convert the time to seconds: 4 minutes * 60 seconds/minute = 240 seconds. Then, calculate the volume filled: 3 L/min * 240 s / 60 s/min = 120 L. The tank drains at 500 mL/s for 10 seconds. First, convert the time to seconds: 10 seconds (no conversion needed). Then, calculate the volume drained: 500 mL/s * 10 s = 5000 mL. Now, convert the volume drained to liters: 5000 mL / 1000 mL/L = 5 L. Now, subtract the volume drained from the volume filled to get the net volume: 120 L - 5 L = 115 L. Answer: 115 L.
detector fmi_4_4_v1: correct unit L
To find the net litres, we need to calculate the volume of water filled and the volume of water drained. The tank fills at 3 L/min for 4 minutes. To find the volume filled, we multiply the rate by the time: 3 L/min × 4 min = 12 L The tank drains at 500 mL/s for 10 seconds. To find the volume drained, we first convert the rate to litres per second (L/s) and then multiply by the time: 500 mL/s = 0.5 L/s (since 1 L = 1000 mL) 0.5 L/s × 10 s = 5 L Now, we subtract the volume drained from the volume filled to find the net litres: 12 L - 5 L = 7 L Answer: 7 L.
detector fmi_4_4_v1: correct unit L
loop 2026-08-15 · meta-llama/llama-3.1-8b-instruct as served · open weights · released 2024-07 · 8B · set s1.2-live · cases v1.4 · conditions v1.0 · ground truth as of 2026-08-09
A tank fills at 3 L/min for 4 minutes, then drains at 500 mL/s for 10 seconds. Net litres?
expected as of 2026-08-09
12 L in, 5 L out, net 7 L. The mixed units are the trap.
Nothing supplied. The baseline.
To find the net volume, we need to calculate the volume filled and the volume drained. The tank fills at 3 L/min for 4 minutes. First, convert the time to seconds: 4 minutes * 60 seconds/minute = 240 seconds. Then, calculate the volume filled: 3 L/min * 240 s / 60 s/min = 120 L. The tank drains at 500 mL/s for 10 seconds. First, convert the time to seconds: 10 seconds (no conversion needed). Then, calculate the volume drained: 500 mL/s * 10 s = 5000 mL. Now, convert the volume drained to liters: 5000 mL / 1000 mL/L = 5 L. Now, subtract the volume drained from the volume filled to get the net volume: 120 L - 5 L = 115 L. Answer: 115 L.
fmi_4_4_v1
detector fmi_4_4_v1: correct unit L
0–20% · whisker = 95% interval
never pooled · a trap ratio would skew the delta
Unchanged by context: 0% with none, 0% with the strongest supplied source. For a control mode that flat line is the result — it is what licenses reading movement elsewhere in this loop as grounding rather than as a document being present. Nothing survives at the best condition on the cases measured here.
- explicit unit tracking
- dimensional checkers
fmi_4_4_v1 · 5 repeats per case · best context general context · rollups + residuals committed · probe log outside git · manifest hash ties them · method