Real context moved 0.0pp on Dimensional-Analysis Failure.
~intervals overlap — not separated from no change
The model produces a quantity with inconsistent or wrong units, or mixes unit systems, yielding a dimensionally invalid result. The rule
A tank fills at 3 L/min for 4 minutes, then drains at 500 mL/s for 10 seconds. Net litres?
First, let's calculate the total volume of water that enters the tank: Volume filled = 3 L/min * 4 min = 12 L Next, let's calculate the total volume of water that leaves the tank: Volume drained = 500 mL/s * 10 s = 5000 mL = 5 L Now, let's find the net volume of water in the tank: Net volume = Volume filled - Volume drained Net volume = 12 L - 5 L Net volume = 7 L Therefore, the net volume of water in the tank is 7 liters. Answer: 7 L
detector fmi_4_4_v1: correct unit L
To find the net litres in the tank, we need to calculate the total volume of water that enters the tank and the total volume of water that leaves the tank. 1. Volume of water that enters the tank: Volume = flow rate x time Volume = 3 L/min x 4 min Volume = 12 L 2. Volume of water that leaves the tank: Volume = flow rate x time Volume = 500 mL/s x 10 s Volume = 5000 mL = 5 L Net litres in the tank = Volume of water that enters the tank - Volume of water that leaves the tank Net litres = 12 L - 5 L Net litres = 7 L Answer: 7 L
detector fmi_4_4_v1: correct unit L
loop 2026-08-15 · openai/gpt-3.5-turbo as served · closed weights · released 2023-03 · set s1.1-live · cases v1.3 · conditions v1.0 · ground truth as of 2026-08-09
A tank fills at 3 L/min for 4 minutes, then drains at 500 mL/s for 10 seconds. Net litres?
expected as of 2026-08-09
12 L in, 5 L out, net 7 L. The mixed units are the trap.
Nothing supplied. The baseline.
First, let's calculate the total volume of water that enters the tank: Volume filled = 3 L/min * 4 min = 12 L Next, let's calculate the total volume of water that leaves the tank: Volume drained = 500 mL/s * 10 s = 5000 mL = 5 L Now, let's find the net volume of water in the tank: Net volume = Volume filled - Volume drained Net volume = 12 L - 5 L Net volume = 7 L Therefore, the net volume of water in the tank is 7 liters. Answer: 7 L
fmi_4_4_v1
detector fmi_4_4_v1: correct unit L
0–40% · whisker = 95% interval
never pooled · a trap ratio would skew the delta
Unchanged by context: 0% with none, 0% with the strongest supplied source. For a control mode that flat line is the result — it is what licenses reading movement elsewhere in this loop as grounding rather than as a document being present. Nothing survives at the best condition on the cases measured here.
- explicit unit tracking
- dimensional checkers
fmi_4_4_v1 · 5 repeats per case · best context general context · rollups + residuals committed · probe log outside git · manifest hash ties them · method