Real context moved 0.0pp on Dimensional-Analysis Failure.
~intervals overlap — not separated from no change
The model produces a quantity with inconsistent or wrong units, or mixes unit systems, yielding a dimensionally invalid result. The rule
A tank fills at 3 L/min for 4 minutes, then drains at 500 mL/s for 10 seconds. Net litres?
To solve the problem, we need to calculate the net amount of liquid in the tank after the filling and draining processes. 1. **Filling the tank:** - The tank fills at a rate of 3 L/min for 4 minutes. - Total volume filled = 3 L/min * 4 min = 12 L 2. **Draining the tank:** - The tank drains at a rate of 500 mL/s for 10 seconds. - First, convert 500 mL/s to L/s: 500 mL/s = 0.5 L/s - Total volume drained = 0.5 L/s * 10 s = 5 L 3. **Net volume in the tank:** - Net volume = Volume filled - Volume drained - Net volume = 12 L - 5 L = 7 L Answer: 7 L
detector fmi_4_4_v1: correct unit L
To determine the net amount of liquid in the tank after the filling and draining processes, we'll calculate each process separately and then find the difference. 1. **Filling the tank:** - Rate: 3 L/min - Time: 4 minutes - Amount filled = Rate × Time = 3 L/min × 4 min = 12 L 2. **Draining the tank:** - Rate: 500 mL/s - Time: 10 seconds - First, convert the rate to litres per second: 500 mL/s = 0.5 L/s - Amount drained = Rate × Time = 0.5 L/s × 10 s = 5 L 3. **Net amount of liquid:** - Net litres = Amount filled - Amount drained = 12 L - 5 L = 7 L Answer: 7 L
detector fmi_4_4_v1: correct unit L
loop 2026-08-15 · mistralai/mistral-small-3.2-24b-instruct as served · open weights · released 2025-06 · 24B · set s1.1-live · cases v1.3 · conditions v1.0 · ground truth as of 2026-08-09
A tank fills at 3 L/min for 4 minutes, then drains at 500 mL/s for 10 seconds. Net litres?
expected as of 2026-08-09
12 L in, 5 L out, net 7 L. The mixed units are the trap.
Nothing supplied. The baseline.
To solve the problem, we need to calculate the net amount of liquid in the tank after the filling and draining processes. 1. **Filling the tank:** - The tank fills at a rate of 3 L/min for 4 minutes. - Total volume filled = 3 L/min * 4 min = 12 L 2. **Draining the tank:** - The tank drains at a rate of 500 mL/s for 10 seconds. - First, convert 500 mL/s to L/s: 500 mL/s = 0.5 L/s - Total volume drained = 0.5 L/s * 10 s = 5 L 3. **Net volume in the tank:** - Net volume = Volume filled - Volume drained - Net volume = 12 L - 5 L = 7 L Answer: 7 L
fmi_4_4_v1
detector fmi_4_4_v1: correct unit L
0–40% · whisker = 95% interval
never pooled · a trap ratio would skew the delta
Unchanged by context: 0% with none, 0% with the strongest supplied source. For a control mode that flat line is the result — it is what licenses reading movement elsewhere in this loop as grounding rather than as a document being present. Nothing survives at the best condition on the cases measured here.
- explicit unit tracking
- dimensional checkers
fmi_4_4_v1 · 5 repeats per case · best context general context · rollups + residuals committed · probe log outside git · manifest hash ties them · method