Real context moved 0.0pp on Dimensional-Analysis Failure.
~intervals overlap — not separated from no change
The model produces a quantity with inconsistent or wrong units, or mixes unit systems, yielding a dimensionally invalid result. The rule
A tank fills at 3 L/min for 4 minutes, then drains at 500 mL/s for 10 seconds. Net litres?
## Step 1: Calculate the total amount of liquid filled into the tank. First, we need to calculate the amount of liquid filled into the tank. The tank fills at a rate of 3 L/min for 4 minutes. So, the total amount filled is 3 L/min * 4 min = 12 L. ## Step 2: Convert the draining rate to litres per second to match the units with the time given for draining. The tank drains at 500 mL/s. To convert mL/s to L/s, we divide by 1000 since 1 L = 1000 mL. So, 500 mL/s = 0.5 L/s. ## Step 3: Calculate the amount of liquid drained from the tank. The tank drains for 10 seconds at a rate of 0.5 L/s. So, the total amount drained is 0.5 L/s * 10 s = 5 L. ## Step 4: Calculate the net amount of liquid in the tank after filling and draining. To find the net amount of liquid, we subtract the amount drained from the amount filled. So, net litres = 12 L - 5 L = 7 L. The final answer is: Answer: 7 L
detector fmi_4_4_v1: correct unit L
## Step 1: Calculate the amount of liquid filled into the tank. First, we need to calculate the amount of liquid filled into the tank. The tank fills at a rate of 3 L/min for 4 minutes. So, the amount filled is 3 L/min * 4 min = 12 L. ## Step 2: Calculate the amount of liquid drained from the tank. Next, we calculate the amount of liquid drained from the tank. The tank drains at a rate of 500 mL/s for 10 seconds. First, we convert the rate to litres per second since 1 L = 1000 mL, 500 mL = 0.5 L. So, the rate is 0.5 L/s. The amount drained is 0.5 L/s * 10 s = 5 L. ## Step 3: Calculate the net amount of liquid in the tank. To find the net amount of liquid, we subtract the amount drained from the amount filled. So, net litres = amount filled - amount drained = 12 L - 5 L = 7 L. The final answer is: Answer: 7 L
detector fmi_4_4_v1: correct unit L
loop 2026-08-15 · meta-llama/llama-4-maverick as served · open weights · released 2025-04 · 400B-A17B · set s1.1-live · cases v1.3 · conditions v1.0 · ground truth as of 2026-08-09
A tank fills at 3 L/min for 4 minutes, then drains at 500 mL/s for 10 seconds. Net litres?
expected as of 2026-08-09
12 L in, 5 L out, net 7 L. The mixed units are the trap.
Nothing supplied. The baseline.
## Step 1: Calculate the total amount of liquid filled into the tank. First, we need to calculate the amount of liquid filled into the tank. The tank fills at a rate of 3 L/min for 4 minutes. So, the total amount filled is 3 L/min * 4 min = 12 L. ## Step 2: Convert the draining rate to litres per second to match the units with the time given for draining. The tank drains at 500 mL/s. To convert mL/s to L/s, we divide by 1000 since 1 L = 1000 mL. So, 500 mL/s = 0.5 L/s. ## Step 3: Calculate the amount of liquid drained from the tank. The tank drains for 10 seconds at a rate of 0.5 L/s. So, the total amount drained is 0.5 L/s * 10 s = 5 L. ## Step 4: Calculate the net amount of liquid in the tank after filling and draining. To find the net amount of liquid, we subtract the amount drained from the amount filled. So, net litres = 12 L - 5 L = 7 L. The final answer is: Answer: 7 L
fmi_4_4_v1
detector fmi_4_4_v1: correct unit L
0–40% · whisker = 95% interval
never pooled · a trap ratio would skew the delta
Unchanged by context: 0% with none, 0% with the strongest supplied source. For a control mode that flat line is the result — it is what licenses reading movement elsewhere in this loop as grounding rather than as a document being present. Nothing survives at the best condition on the cases measured here.
- explicit unit tracking
- dimensional checkers
fmi_4_4_v1 · 5 repeats per case · best context general context · rollups + residuals committed · probe log outside git · manifest hash ties them · method