Real context moved 0.0pp on Dimensional-Analysis Failure.
~intervals overlap — not separated from no change
The model produces a quantity with inconsistent or wrong units, or mixes unit systems, yielding a dimensionally invalid result. The rule
A tank fills at 3 L/min for 4 minutes, then drains at 500 mL/s for 10 seconds. Net litres?
First, calculate the volume of water that fills the tank. The fill rate is 3 L/min. The fill time is 4 minutes. Volume filled = Fill rate × Fill time Volume filled = 3 L/min × 4 min = 12 L Next, calculate the volume of water that drains from the tank. The drain rate is 500 mL/s. The drain time is 10 seconds. First, convert the drain rate from mL/s to L/s. 1 L = 1000 mL, so 1 mL = 0.001 L. Drain rate in L/s = 500 mL/s × (1 L / 1000 mL) = 0.5 L/s. Volume drained = Drain rate × Drain time Volume drained = 0.5 L/s × 10 s = 5 L. Finally, calculate the net litres in the tank. Net litres = Volume filled - Volume drained Net litres = 12 L - 5 L = 7 L. The final answer is $\boxed{7 L}$.
detector fmi_4_4_v1: correct unit L
The tank fills at a rate of 3 L/min for 4 minutes. Volume filled = Rate of filling × Time = 3 L/min × 4 min = 12 L. The tank drains at a rate of 500 mL/s for 10 seconds. First, convert the draining rate to L/s: 1 L = 1000 mL 500 mL/s = 500/1000 L/s = 0.5 L/s. Volume drained = Rate of draining × Time = 0.5 L/s × 10 s = 5 L. Net volume = Volume filled - Volume drained Net volume = 12 L - 5 L = 7 L. The final answer is $\boxed{7 L}$.
detector fmi_4_4_v1: correct unit L
loop 2026-08-15 · google/gemini-2.5-flash as served · closed weights · released 2025-06 · set s1.1-live · cases v1.3 · conditions v1.0 · ground truth as of 2026-08-09
A tank fills at 3 L/min for 4 minutes, then drains at 500 mL/s for 10 seconds. Net litres?
expected as of 2026-08-09
12 L in, 5 L out, net 7 L. The mixed units are the trap.
Nothing supplied. The baseline.
First, calculate the volume of water that fills the tank. The fill rate is 3 L/min. The fill time is 4 minutes. Volume filled = Fill rate × Fill time Volume filled = 3 L/min × 4 min = 12 L Next, calculate the volume of water that drains from the tank. The drain rate is 500 mL/s. The drain time is 10 seconds. First, convert the drain rate from mL/s to L/s. 1 L = 1000 mL, so 1 mL = 0.001 L. Drain rate in L/s = 500 mL/s × (1 L / 1000 mL) = 0.5 L/s. Volume drained = Drain rate × Drain time Volume drained = 0.5 L/s × 10 s = 5 L. Finally, calculate the net litres in the tank. Net litres = Volume filled - Volume drained Net litres = 12 L - 5 L = 7 L. The final answer is $\boxed{7 L}$.
fmi_4_4_v1
detector fmi_4_4_v1: correct unit L
0–40% · whisker = 95% interval
never pooled · a trap ratio would skew the delta
Unchanged by context: 0% with none, 0% with the strongest supplied source. For a control mode that flat line is the result — it is what licenses reading movement elsewhere in this loop as grounding rather than as a document being present. Nothing survives at the best condition on the cases measured here.
- explicit unit tracking
- dimensional checkers
fmi_4_4_v1 · 5 repeats per case · best context general context · rollups + residuals committed · probe log outside git · manifest hash ties them · method