Real context moved 0.0pp on Dimensional-Analysis Failure.
~intervals overlap — not separated from no change
The model produces a quantity with inconsistent or wrong units, or mixes unit systems, yielding a dimensionally invalid result. The rule
A tank fills at 3 L/min for 4 minutes, then drains at 500 mL/s for 10 seconds. Net litres?
Let's break down the problem step by step: 1. **Filling phase:** - Rate: 3 L/min - Time: 4 minutes - Volume filled: \( 3 \, \text{L/min} \times 4 \, \text{min} = 12 \, \text{L} \) 2. **Draining phase:** - Rate: 500 mL/s - Convert to litres per second: \( 500 \, \text{mL/s} = 0.5 \, \text{L/s} \) (since 1 L = 1000 mL) - Time: 10 seconds - Volume drained: \( 0.5 \, \text{L/s} \times 10 \, \text{s} = 5 \, \text{L} \) 3. **Net volume change:** - Net litres = Volume filled - Volume drained = \( 12 \, \text{L} - 5 \, \text{L} = 7 \, \text{L} \) Answer: 7 L
detector fmi_4_4_v1: correct unit L
First, calculate the total volume added during the filling phase: Filling rate = 3 L/min Time = 4 minutes Volume filled = 3 L/min × 4 min = 12 L Next, calculate the total volume drained during the draining phase: Draining rate = 500 mL/s Convert to litres: 500 mL/s = 0.5 L/s (since 1 L = 1000 mL) Time = 10 seconds Volume drained = 0.5 L/s × 10 s = 5 L Now, find the net volume: Net volume = Volume filled - Volume drained = 12 L - 5 L = 7 L Answer: 7 L
detector fmi_4_4_v1: correct unit L
loop 2026-08-15 · deepseek/deepseek-chat-v3.1 as served · open weights · released 2025-08 · 671B-A37B · set s1.1-live · cases v1.3 · conditions v1.0 · ground truth as of 2026-08-09
A tank fills at 3 L/min for 4 minutes, then drains at 500 mL/s for 10 seconds. Net litres?
expected as of 2026-08-09
12 L in, 5 L out, net 7 L. The mixed units are the trap.
Nothing supplied. The baseline.
Let's break down the problem step by step: 1. **Filling phase:** - Rate: 3 L/min - Time: 4 minutes - Volume filled: \( 3 \, \text{L/min} \times 4 \, \text{min} = 12 \, \text{L} \) 2. **Draining phase:** - Rate: 500 mL/s - Convert to litres per second: \( 500 \, \text{mL/s} = 0.5 \, \text{L/s} \) (since 1 L = 1000 mL) - Time: 10 seconds - Volume drained: \( 0.5 \, \text{L/s} \times 10 \, \text{s} = 5 \, \text{L} \) 3. **Net volume change:** - Net litres = Volume filled - Volume drained = \( 12 \, \text{L} - 5 \, \text{L} = 7 \, \text{L} \) Answer: 7 L
fmi_4_4_v1
detector fmi_4_4_v1: correct unit L
0–40% · whisker = 95% interval
never pooled · a trap ratio would skew the delta
Unchanged by context: 0% with none, 0% with the strongest supplied source. For a control mode that flat line is the result — it is what licenses reading movement elsewhere in this loop as grounding rather than as a document being present. Nothing survives at the best condition on the cases measured here.
- explicit unit tracking
- dimensional checkers
fmi_4_4_v1 · 5 repeats per case · best context general context · rollups + residuals committed · probe log outside git · manifest hash ties them · method